Originally Posted by
MrWizard Find 2 values of x that make f(x) = 0.
f(x) = (x-a)(x-b)(x-c)
The obvious answers are x = {a, b, c}, but considering this is a calculus class where he usually assigns pretty challenging homework there must be another solution. There are 2 more parts to the question if it will help you understand where hes heading:
2. Find the average of the two values of x you found above. What point on the graph of f has this x-value?
3. Find the equation for the tangent line at the point you found above, and find all points where the tangent line intersects the graph y = f(x), where f is defined above.
I don't want to be given the answers, but I would like some sort of recommendation on how to address the problem.
Thanks for any help in advance.