The area bounded by the graphs of y=e^(-2x), y=-e^(x), x=0, and x=2 is what? I am having a hard time integrating. Thanks for the help.
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Originally Posted by nystudent2729 The area bounded by the graphs of y=e^(-2x), y=-e^(x), x=0, and x=2 is what? I am having a hard time integrating. Thanks for the help. clearly $\displaystyle y=e^{-2x}$ is greater on this interval by plugging in say 1. so $\displaystyle \int e^{-2x} +e^{x}$ Can you integrate this? Hint $\displaystyle \int e^{x}=e^{x}$
top function - bottom function ... $\displaystyle A = \int_0^2 e^{-2x} - (-e^x) \, dx$
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