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Math Help - Ugly integral

  1. #1
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    Ugly integral

    Hello
    was wondering if someone could help me with this integral.
    Integral (Square root(arctanx))/(1+(x^2))
    I have no clue how to work with the arctanx, i know it is tan^-1(x)
    Thanks in advance for the help.
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  2. #2
    MHF Contributor red_dog's Avatar
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    \arctan x=t\Rightarrow\frac{1}{1+x^2}dx=dt

    Then I=\int\sqrt{t}dt=\frac{2}{3}t\sqrt{t}+C
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