Hello was wondering if someone could help me with this integral. Integral (Square root(arctanx))/(1+(x^2)) I have no clue how to work with the arctanx, i know it is tan^-1(x) Thanks in advance for the help.
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$\displaystyle \arctan x=t\Rightarrow\frac{1}{1+x^2}dx=dt$ Then $\displaystyle I=\int\sqrt{t}dt=\frac{2}{3}t\sqrt{t}+C$
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