integration of powers

**twilightstr** · February 10th 2009, 11:35 PM

integrate 1/(x+x^(1/3))

**ADARSH** · February 11th 2009, 12:15 AM

Originally Posted by twilightstr

integrate 1/(x+x^(1/3))

put $x^{\frac{1}{3}} =t$
so
$\frac{x^{\frac{-2}{3}}dx}{3} = dt$

thus

$dx = 3t^2dt$
So
$\int{\frac{dx}{x+x^{1/3}} }$

$<br /> = \int{\frac{3t^2dt}{t^3+t} }<br />$

Go ahead!

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