
integration of powers

Quote:
Originally Posted by
twilightstr integrate 1/(x+x^(1/3))
put $\displaystyle x^{\frac{1}{3}} =t$
so
$\displaystyle \frac{x^{\frac{2}{3}}dx}{3} = dt$
thus
$\displaystyle dx = 3t^2dt$
So
$\displaystyle \int{\frac{dx}{x+x^{1/3}} } $
$\displaystyle
= \int{\frac{3t^2dt}{t^3+t} }
$
(Wait)Go ahead!