Find the integral of (x^2+4)/(x^2-4) dx.

The answer is x + 2 ln | x-2/x+2 |

Here's what I did so far:

(x^2+4)/(x^2-4) = (x^2+4)/[x+2][x-2].

I'm not really sure how to split them apart. I tried making it Ax+B/x+2 + Cx+D/x-2 but when I worked it out I got: A+C = 1, C-B = 2..? I don't think that was right.

Thank you for your help!!