I'm supposed to change this cartesian integral into a polar integral.
(integral from y=0 to y=2)(integral from x=-(sqrt(1-(y-1)^2)) to x=0) of xy^2 dxdy
I got the polar equivalent to be:
(integral from theta=-pi/2 to pi/2)(integral from r=0 to r=1) of r^4(costheta)(sin^2theta) drdtheta
Have I done this correctly??
Re: Expressing the circle in polar form. Reading this thread might help: http://www.mathhelpforum.com/math-he...variables.html