I'm not sure what the curve of x=-(sqrt(1-(y-1)^2)) would look like....anyone know??

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- Feb 10th 2009, 01:20 PMs7bCurves
I'm not sure what the curve of x=-(sqrt(1-(y-1)^2)) would look like....anyone know??

- Feb 10th 2009, 01:53 PMJameson
- Feb 10th 2009, 01:57 PMs7b
oh ok, so i think it would be a circle of radius one centered about (0,1) ??

- Feb 10th 2009, 02:03 PMJameson
- Feb 10th 2009, 02:08 PMs7b
Would that mean that it is reflected in the x-axis giving a circle of radius one centered at (0,-1)

- Feb 10th 2009, 02:13 PMJameson
When you take conics and apply a square root, the result is a split in the graph. In your problem x is always going to be negative so I believe this implies that it is the circle you first mentioned, cut in half vertically, and the left side of the half circle.