please, someone help, how would i do $\displaystyle x^2 + 2(x^2)y + 3xy = 0$ with implicit differential..
also, how would i find $\displaystyle f'(-t cos(PI/t) (PI)$ (t^-2)$\displaystyle (sin(PI/2)))$ there are more than two terms
thanks
please, someone help, how would i do $\displaystyle x^2 + 2(x^2)y + 3xy = 0$ with implicit differential..
also, how would i find $\displaystyle f'(-t cos(PI/t) (PI)$ (t^-2)$\displaystyle (sin(PI/2)))$ there are more than two terms
thanks
If you have a function f(x,y) = 0 then you can differentiate it using the formula:
$\displaystyle f(x,y)=0~\implies~\dfrac{dy}{dx}=y'=-\dfrac{\frac{\partial f}{\partial x}}{\frac{\partial f}{\partial y}}$
With your function you'll get:
$\displaystyle y'=-\dfrac{2x+4xy+3y}{2x^2+3x}$
---------------------------------------------------------------------
If you don't want to use this formula differentiate the given equation wrt x:
$\displaystyle x^2 + 2(x^2)y + 3xy = 0~\implies~2x+(4x\cdot y + 2x^2 \cdot y') + (3y+3x\cdot y')=0$
Expand the brackets and collect all terms containing y' at the LHS:
$\displaystyle 2x^2y'+3xy'=-2x-4xy-3y$
Factor out y' and divide both sides by the bracket. You'll get the result which you've got by the formula too.