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Thread: [SOLVED] Integration

  1. February 9th 2009, 04:19 PM #1
    kinana18
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    Question [SOLVED] Integration

    2du/1+3u
    How do you integrate this?
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  2. February 9th 2009, 04:50 PM #2
    Jake8054
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    Move the 2 outside the integral then use substitution where v=1+3u. You should get (2/3)ln(abs(1+3u)).
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  3. February 9th 2009, 04:52 PM #3
    skeeter
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    Quote Originally Posted by kinana18 View Post
    2du/1+3u
    How do you integrate this?
    \int \frac{2}{1+3u} du = \frac{2}{3} \int \frac{3}{1+3u} du = \frac{2}{3} \ln|1 + 3u| + C <br />
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