# Math Help - Integration 2

1. ## Integration 2

dx/3((2x-1)^2)
How do you integrate by substitution?

2. Originally Posted by kinana18
dx/3((2x-1)^2)
How do you integrate by substitution?
$\int \frac{dx}{3(2x-1)^2}$

$u = 2x-1$

$\frac{du}{dx} = 2$

$\frac{1}{2} du = dx$

$\int \frac{\frac{1}{2}du}{3u^2}$

$\frac{1}{2} . \frac{1}{3}\int \frac{du}{u^2}$

$\frac{1}{6} \int u^{-2}du$