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Math Help - Integration 2

  1. #1
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    Question Integration 2

    dx/3((2x-1)^2)
    How do you integrate by substitution?
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  2. #2
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    Quote Originally Posted by kinana18 View Post
    dx/3((2x-1)^2)
    How do you integrate by substitution?
     \int \frac{dx}{3(2x-1)^2}

     u = 2x-1

     \frac{du}{dx} = 2

     \frac{1}{2} du = dx

     \int \frac{\frac{1}{2}du}{3u^2}

     \frac{1}{2} . \frac{1}{3}\int \frac{du}{u^2}

     \frac{1}{6} \int u^{-2}du
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