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Math Help - Integration Question

  1. #1
    Junior Member
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    Integration Question

    The Integral of 1/<br />
(2x+3)

    I am wondering if I could pull out the 2 from the denominator? So, I'd end up with 1/(2(x+3/2)) Then could I just do 1/2 the integral of  1/(x+(3/2)) which is ln(x + 3/2)? so the answer would be 1/2 LN(x+ 3/2)?

    Is there a better way, or a correct way to solve this?

    Thank you
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  2. #2
    Math Engineering Student
    Krizalid's Avatar
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    Just put u=2x+3 and you'll arrive at \frac12\int\frac{du}u=\frac12\ln|u|+k. Just back-substitute.
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