Integrate the following: ln(x)^2/x dx I get stuck when I do the u-subxtitution.
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If it's $\displaystyle \ln x^2,$ then it's quite easy since $\displaystyle \ln x^2=2\ln x,$ so worry about by $\displaystyle \int\frac{\ln x}x\,dx.$
If indeed it is $\displaystyle \int\frac{(ln x)^2}{x}dx= \int(ln x)^2(dx/x)$, then use the substitution u= ln(x). Since du/dx= 1/x, du= dx/x and the integral becomes $\displaystyle \int u^2 du$.
thanks!!!
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