Find an antiderivative. How do you integrate ( 1 / [(cos ^ 2) t]) ?? The antiderivative of Cos(t) = sine(t), then I am lost. Help please!
Follow Math Help Forum on Facebook and Google+
Recall that: $\displaystyle \frac{1}{\cos x} = \sec x$ So you have: $\displaystyle \int p(t) dt = \int \left(\cos t + \sec^2 t\right) dt$ Do you remember anything whose derivative is equal to $\displaystyle \sec^2 t$ ?
Tan(t) ? haha
View Tag Cloud