Find the limit of (sin x)/x as x--> 0
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Originally Posted by magentarita Find the limit of (sin x)/x as x--> 0 Without knowing L'Hopital's Rule, one can show this is the case using the Squeeze Theorem. You can find a proof here.
For simplicity sinx can be expanded as So the Limit now becomes Its better if you follow Chris
Last edited by Krizalid; February 9th 2009 at 01:49 AM.
Thank you but I am still a little lost here.
magentarita's not ready to diggest ADARSH's post since he/she's covering limits. But, follow Chris L T521's link, which provides a geometric proof.
Originally Posted by Krizalid magentarita's not ready to diggest ADARSH's post since he/she's covering limits. But, follow Chris L T521's link, which provides a geometric proof. You are right but this is the main reason why I post questions here---to learn, that it.
Or you can use the definition of the derivative : let f be the sine function, and a=0, remember that the derivative of the sine function is cosine, and observe I guess this method suits the most what you're currently doing...
Originally Posted by Moo Or you can use the definition of the derivative : let f be the sine function, and a=0, remember that the derivative of the sine function is cosine, and observe How do you think the derivative of sine is derived in the first place!
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