Find the volume of the region bounded by the following curves rotated about the x-axis:

$\displaystyle y = 41sinx$ and $\displaystyle y = 0 $ from $\displaystyle \frac{\pi}{2} \leq x \leq \pi$

Here is what I have so far:

$\displaystyle V = \int\limits^{\pi}_{\frac{\pi}{2}} 41\pi x sinx dx$

Then I'm stuck