# Thread: [SOLVED] Trig integral in volume of rotation

1. ## [SOLVED] Trig integral in volume of rotation

Find the volume of the region bounded by the following curves rotated about the x-axis:

$y = 41sinx$ and $y = 0$ from $\frac{\pi}{2} \leq x \leq \pi$

Here is what I have so far:

$V = \int\limits^{\pi}_{\frac{\pi}{2}} 41\pi x sinx dx$

Then I'm stuck

2. It's solved... Anyways, I suggest you to use the disk method for this problem

$V=\pi\int_\frac{\pi}{2}^\pi (41\sin x)^2 dx$.