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Math Help - [SOLVED] Trig integral in volume of rotation

  1. #1
    Senior Member mollymcf2009's Avatar
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    [SOLVED] Trig integral in volume of rotation

    Find the volume of the region bounded by the following curves rotated about the x-axis:

    y = 41sinx and y = 0 from \frac{\pi}{2} \leq x \leq \pi

    Here is what I have so far:

    V = \int\limits^{\pi}_{\frac{\pi}{2}} 41\pi x sinx dx

    Then I'm stuck
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  2. #2
    Member Abu-Khalil's Avatar
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    It's solved... Anyways, I suggest you to use the disk method for this problem

    V=\pi\int_\frac{\pi}{2}^\pi (41\sin x)^2 dx.
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