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Math Help - Limit Problem

  1. #1
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    Limit Problem

    Lim x -> 0

    1-cos5x / x

    Thanks in advance
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  2. #2
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    Quote Originally Posted by Afterme View Post
    Lim x -> 0

    1-cos5x / x

    Thanks in advance
    Lim 1-cos5x / x
    x -> 0

    o/o tope

    You know the limit

    lim ( cosx-1)/ x = 0
    x-->0

    Lets use it

    Lim -(cos5x -1) / x
    x -> 0

    multiply top and bottom by 5

    Lim -5(cos5x -1) / 5x
    x -> 0

    t = 5x

    Lim -5(cost -1) / t = 0
    x -> 0
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  3. #3
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    Quote Originally Posted by Afterme View Post
    Lim x -> 0

    1-cos5x / x

    Thanks in advance
    \lim_{x\to 0}{\frac{1 - \cos (5x)}{x}}= (by using l'hospital's rule)  \lim_{x\to 0}{5 \sin x}= 5 \sin 0= 5 \cdot 0 = 0
    Last edited by mr fantastic; February 9th 2009 at 03:25 AM. Reason: Tidied up the latex
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