i need a lot of help intergrating...it's really hard...The way we're supposed to do it is by parts or trig substitution. dx ([x^2]-4x)^(3/2) any help would be awesome, thanks!
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Is it meant to look like this $\displaystyle \int (x^2 - 4x)^{\frac{3}{2}}.dx$
ahh no soryr, the dx is supposed to be on top, either dx on top or a -(3/2) as the exponent
Put $\displaystyle x=\frac{4}{1-{{u}^{2}}},$ and show us where does that get you.
will that get me to parts or trig substitution?
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