Hello,
But if you let , you can see that
thus (x-3) is a factor of
more precisely,
and you can calculate the limit !
Hi
The question is "find the value of k for each of the following functions that make them continueous everywhere"
F(x) = (2x^2-x-15)/(x-3) if x<3
and
F(x) = kx-1 if x >=3
What I don't understand is how you solve this if
lim f(x) = lim (2x^2-x-15)/(x-3) does not exist since you can't
x->3- x->3-
divide by zero.
I have six calculus books I am looking through and I can't find a single example of this. Any enlightenment would be greatly appreciated.
Thanks in advance from
this calculus beginner