Fing the arc length of the graph of the function over the indicated interval.
y = (x^4)/(8) - (1/(4x^2))
on interval [1,2]
$\displaystyle
y'= \frac {1}{2}x^3 - \frac {1}{2x^3}$ on int [1,2]
$\displaystyle
= \int \sqrt{1+ (\frac {1}{2}x^3 - \frac {1}{2x^3})^2}
$
I don't know how to square this and combine it with the 1. I understand how to integrate it from there but, combining this is really stumping me.