can anyone tell me what the the value of this is - i think it is ln(1/3) but my book says ln(3) $\displaystyle \int\limits_{ - \infty }^2 {[\frac{1}{{x - 1}}} - \frac{1}{{x + 1}}]dx $
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$\displaystyle \left. \ln \left| \frac{x-1}{x+1} \right| \right|_{-\infty }^{2}=\ln \left( \frac{1}{3} \right)=-\ln 3.$
woot book is wrong i am right ty
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