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Math Help - Easy improper integral

  1. #1
    Member billa's Avatar
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    Easy improper integral

    can anyone tell me what the the value of this is - i think it is ln(1/3) but my book says ln(3)

    <br />
\int\limits_{ - \infty }^2 {[\frac{1}{{x - 1}}}  - \frac{1}{{x + 1}}]dx<br />
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  2. #2
    Math Engineering Student
    Krizalid's Avatar
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    \left. \ln \left| \frac{x-1}{x+1} \right| \right|_{-\infty }^{2}=\ln \left( \frac{1}{3} \right)=-\ln 3.
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  3. #3
    Member billa's Avatar
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    woot book is wrong i am right

    ty
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