Easy improper integral

Printable View

February 6th 2009, 05:05 PM
billa

Easy improper integral

can anyone tell me what the the value of this is - i think it is ln(1/3) but my book says ln(3)

$<br /> \int\limits_{ - \infty }^2 {[\frac{1}{{x - 1}}} - \frac{1}{{x + 1}}]dx<br />$
February 6th 2009, 05:35 PM
Krizalid

$\left. \ln \left| \frac{x-1}{x+1} \right| \right|_{-\infty }^{2}=\ln \left( \frac{1}{3} \right)=-\ln 3.$
February 6th 2009, 05:36 PM
billa

woot book is wrong i am right

ty

All times are GMT -8. The time now is 06:39 AM.