Find dy/dx in terms of x and y
ln(x²+1) + ln(y+1) = x + y
thanks any help is fab
Hello, gracey!
Exactly where is your difficulty?
Differentiate implicitly and solve for $\displaystyle \frac{dy}{dx}$Find $\displaystyle \frac{dy}{dx}$ in terms of $\displaystyle x\text{ and }y$
. . $\displaystyle \ln(x^2+1) + \ln(y+1) \:=\: x + y $
. . $\displaystyle \frac{2x}{x^2+1} + \frac{\frac{dy}{dx}}{u+1} \:=\:1 + \frac{dy}{dx}$ . . . . did you get this far?
The rest is just algebra . . .