in that case, we have
V = 16h
that's it. so h = V/16
now differentiate both sides with respect to time and plug in dV/dt
the reservoir is the cone?#2 A cone is filled with water at a rate of 6m^3/min.
If the reservoir is 3 m deep, and has a 4 m radius at the top, what is the rate at which the surface level of the water is rising at the instant the depth of the water is 2 m?
My answer: dh/dt = 16/6pi.
Are these answers right?
that's not the answer i got. what equation did you use?