Results 1 to 2 of 2

Math Help - Area Enlcosed By Curves

  1. #1
    Member
    Joined
    Nov 2008
    Posts
    76

    Area Enlcosed By Curves

    Find the area of the region enclosed by the curves:

    2y=4*sqrtx, y = 4, 2y + 3x = 7

    I'm having a little difficulty with this problem. Is the upper bound function y=4?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Member Abu-Khalil's Avatar
    Joined
    Oct 2008
    From
    Santiago
    Posts
    148
    Yes, the upper bound function is y=4.

    I suggest you to do a graph of the situation to follow my answer.

    First, we'll find the intersection between 2y+3x=7 and y=4. Just replacing, we obtain 8+3x=7\Rightarrow x=-\frac{1}{3}, \therefore the functions intersects at \left(-\frac{1}{3},4\right).

    Doing the same, we conclude that 2y+3x=7 and y=2\sqrt{x} insersects at \left(1,2\right).

    Finally, the area is given by \int_{-\frac{1}{3}}^14-\left(-\frac{3}{2}x+\frac{7}{2}\right)dx+\int_1^44-2\sqrt{x}dx.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Area between Curves
    Posted in the Calculus Forum
    Replies: 2
    Last Post: March 15th 2011, 04:24 PM
  2. Area between two curves
    Posted in the Calculus Forum
    Replies: 1
    Last Post: August 11th 2010, 10:52 PM
  3. area between curves.
    Posted in the Calculus Forum
    Replies: 6
    Last Post: January 11th 2010, 12:39 PM
  4. Area Between Two Curves
    Posted in the Calculus Forum
    Replies: 1
    Last Post: March 10th 2009, 04:15 PM
  5. Area between two curves
    Posted in the Calculus Forum
    Replies: 2
    Last Post: January 27th 2009, 05:59 PM

Search Tags


/mathhelpforum @mathhelpforum