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Math Help - Urgent Integration Help

  1. #16
    Math Engineering Student
    Krizalid's Avatar
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    \int{{{\sec }^{3}}x\,dx}=\sec x\tan x-\int{\left( {{\sec }^{3}}x-\sec x \right)\,dx}, so

    2\int{{{\sec }^{3}}x\,dx}=\sec x\tan x+\int{\sec x\,dx}, and few post ago I told ya how to integrate the last integral.
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  2. #17
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    Quote Originally Posted by Krizalid View Post
    \int{{{\sec }^{3}}x\,dx}=\sec x\tan x-\int{\left( {{\sec }^{3}}x-\sec x \right)\,dx}, so

    2\int{{{\sec }^{3}}x\,dx}=\sec x\tan x+\int{\sec x\,dx}, and few post ago I told ya how to integrate the last integral.
    I cannot thank you enough for your help. Thanks for the patience and tremendous help.
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