# Math Help - Urgent Integration Help

1. $\int{{{\sec }^{3}}x\,dx}=\sec x\tan x-\int{\left( {{\sec }^{3}}x-\sec x \right)\,dx},$ so

$2\int{{{\sec }^{3}}x\,dx}=\sec x\tan x+\int{\sec x\,dx},$ and few post ago I told ya how to integrate the last integral.

2. Originally Posted by Krizalid
$\int{{{\sec }^{3}}x\,dx}=\sec x\tan x-\int{\left( {{\sec }^{3}}x-\sec x \right)\,dx},$ so

$2\int{{{\sec }^{3}}x\,dx}=\sec x\tan x+\int{\sec x\,dx},$ and few post ago I told ya how to integrate the last integral.
I cannot thank you enough for your help. Thanks for the patience and tremendous help.

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