1. ## [SOLVED] differentiate

v=$\displaystyle 3x^2y^2$

dv/dx=
dv/dy=

2. Originally Posted by ronaldo_07
v=$\displaystyle 3x^2y^2$

dv/dx=
dv/dy=

hi
when you differentiate with respect to x then consider y as constant
same with other

3. so would the answer be

dv/dx=$\displaystyle 6xy^2$

dv/dy=$\displaystyle 6x^2y$

4. Originally Posted by ronaldo_07
dv/dx=$\displaystyle 6xy^2$
dv/dy=$\displaystyle 6x^2y$