v=$\displaystyle 3x^2y^2$ dv/dx= dv/dy= how would i answer these?
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Originally Posted by ronaldo_07 v=$\displaystyle 3x^2y^2$ dv/dx= dv/dy= how would i answer these? hi when you differentiate with respect to x then consider y as constant same with other
so would the answer be dv/dx=$\displaystyle 6xy^2$ dv/dy=$\displaystyle 6x^2y$
Originally Posted by ronaldo_07 so would the answer be dv/dx=$\displaystyle 6xy^2$ dv/dy=$\displaystyle 6x^2y$ yes
thanks dude
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