0 int 0.2
1/(1+x^5) dx
need to use power series to approximate the definate integral.
thankyou for help on this one!
From the geometric power series
$\displaystyle \frac{1}{1+x} = 1 - x + x^2 - x^3 + - \cdots $
$\displaystyle \frac{1}{1+x^5} = 1 - x^5 + x^{10} - x^{15} + - \cdots $
so
$\displaystyle \int_0^{0.2}\frac{1}{1+x^5}\, dx = \int_0^{0.2} 1 - x^5 + x^{10} - x^{15} + - \cdots \, dx$
and integrate term-by-term (you won't need a lot of terms to get a really accurate answer)