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Math Help - Complex Problem

  1. #1
    Junior Member
    Joined
    Mar 2008
    Posts
    33

    Complex Problem

    Let X be the path with parametrisation

    f(t)=2-i-3e^(it) (t E [1/2pi, 2pi]

    Sketch X

    I think I know how to sketch the graph once I get the parametric equations, but I cant seem to get my head around them.

    I know that the parametric equation for x will have 2 in it and the one for y will have the -i which will become -1, but its the 3e^(it) value that is confusing me. Do I need to do something to this value to make it more simplified? Any help would be great?

    Thanx

    Bex
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  2. #2
    MHF Contributor
    Joined
    Nov 2008
    From
    France
    Posts
    1,458
    Hi

    f(t)=2-i-3e^{it}
    f(t)=2-i-3 (\cos t + i \sin t)

    Thus
    x(t)=2 - 3 \cos t
    y(t)=-1-3 \sin t
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  3. #3
    Junior Member
    Joined
    Mar 2008
    Posts
    33

    Thanks

    Thanks for your help. I am finally able to sketch the graph
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