Hi
Thus
Let X be the path with parametrisation
f(t)=2-i-3e^(it) (t E [1/2pi, 2pi]
Sketch X
I think I know how to sketch the graph once I get the parametric equations, but I cant seem to get my head around them.
I know that the parametric equation for x will have 2 in it and the one for y will have the -i which will become -1, but its the 3e^(it) value that is confusing me. Do I need to do something to this value to make it more simplified? Any help would be great?
Thanx
Bex