# Complex Problem

• February 5th 2009, 07:26 AM
bex23
Complex Problem
Let X be the path with parametrisation

f(t)=2-i-3e^(it) (t E [1/2pi, 2pi]

Sketch X

I think I know how to sketch the graph once I get the parametric equations, but I cant seem to get my head around them.

I know that the parametric equation for x will have 2 in it and the one for y will have the -i which will become -1, but its the 3e^(it) value that is confusing me. Do I need to do something to this value to make it more simplified? Any help would be great?

Thanx

Bex
• February 5th 2009, 08:26 AM
running-gag
Hi

$f(t)=2-i-3e^{it}$
$f(t)=2-i-3 (\cos t + i \sin t)$

Thus
$x(t)=2 - 3 \cos t$
$y(t)=-1-3 \sin t$
• February 6th 2009, 04:39 AM
bex23
Thanks
Thanks for your help. I am finally able to sketch the graph (Clapping)