
Complex Problem
Let X be the path with parametrisation
f(t)=2i3e^(it) (t E [1/2pi, 2pi]
Sketch X
I think I know how to sketch the graph once I get the parametric equations, but I cant seem to get my head around them.
I know that the parametric equation for x will have 2 in it and the one for y will have the i which will become 1, but its the 3e^(it) value that is confusing me. Do I need to do something to this value to make it more simplified? Any help would be great?
Thanx
Bex

Hi
$\displaystyle f(t)=2i3e^{it}$
$\displaystyle f(t)=2i3 (\cos t + i \sin t)$
Thus
$\displaystyle x(t)=2  3 \cos t$
$\displaystyle y(t)=13 \sin t$

Thanks
Thanks for your help. I am finally able to sketch the graph (Clapping)