An incorrect use of L hospital rule is illustrated in the following limit computation.Explain what is wrong and find correct value of limit.
lim x->pi/2 (sinx/x)= lim x->pi/2 (cosx/1)=0
Hello, Bobby77!
An incorrect use of L'Hopital's Rule is illustrated in the following limit computation.
Explain what is wrong and find correct value of limit.
To apply L'Hopital's Rule, the function must approach an indeterminate form:
. .
This limit exists: .