An incorrect use of L hospital rule is illustrated in the following limit computation.Explain what is wrong and find correct value of limit.

lim x->pi/2 (sinx/x)= lim x->pi/2 (cosx/1)=0

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- Nov 4th 2006, 10:38 AMbobby77limit of function.
An incorrect use of L hospital rule is illustrated in the following limit computation.Explain what is wrong and find correct value of limit.

lim x->pi/2 (sinx/x)= lim x->pi/2 (cosx/1)=0 - Nov 4th 2006, 10:42 AMPlato
- Nov 4th 2006, 01:55 PMSoroban
Hello, Bobby77!

Quote:

An incorrect use of L'Hopital's Rule is illustrated in the following limit computation.

Explain what is wrong and find correct value of limit.

To apply L'Hopital's Rule, the function__must__approach an indeterminate form:

. .

This limit exists: .