Thread: Vector calc center and radius of circle problem

I am studying for a test and one of the review questions is stumping me.

I am suppose to find the center and radius of a circle with the following equation:

x^2 + 4x + y^2 - 6y + z^2 + 12z = 0

I know that the equation for a sphere is x^2 + y^2 + z^2 = radius ^2

Also I think that you would take (x - x at center)^2 + (y- y at center)^2 + (z -- z at center)^2 and this is equal to the radius squared. But I do not know how to deal with 4x, -6y and 12z.
Thanks to all you math enlightened folks for all the help that I have received for the past year!

complete the square for x , y, and z ...





can you finish?

Thanks so much for your quick assistance.

I see that by completing the squares we would have the square of the radius as 49 and therefore the radius is 7. I also see that the center coordinate would involve 2,3,6 but I think it would be (2, -3, 6) and the answer says it should be (-2,3, -6)????

the book answer is correct



center at