The algebra is the booger in these things more than anything.
Using the right end method.
Now, expand out:
Use the formulae for the sum of the squares and integers.
Now, take the limit:
Now, you can see the 4.5...right?.
Could somone show me how the integral X^2-7X+10 on [2,5] would be equal to -4.5. I know that given RHS= F(Xi)delta x the delta is 3/n and Xi is 1+3i/n so I know how to start like this.
(1+(3i/n)^2-7(1+(3i/n))+10)(3/n)
I just don't see how I would break this down.
I know that after it is simplifed I need to take the limit as n approaches postive infintiy.