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Math Help - area of a hyperbola

  1. #1
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    area of a hyperbola

    hey... i've been trying this problem for like 30 minutes and I can't seem to get it. I keep ending up with a weird integrand with 12 (sec cubed x -sec x). Can someone explain how to go about this? (we're doing trigonomentric substitution in calc 2)

    Find the area of the region bounded by the hyperbola 9x2 - 4y2 = 36 and the line x = 3.
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  2. #2
    Senior Member DeMath's Avatar
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    Quote Originally Posted by chubigans View Post
    hey... i've been trying this problem for like 30 minutes and I can't seem to get it. I keep ending up with a weird integrand with 12 (sec cubed x -sec x). Can someone explain how to go about this? (we're doing trigonomentric substitution in calc 2)

    Find the area of the region bounded by the hyperbola 9x2 - 4y2 = 36 and the line x = 3.
    You should have received this integral \int\limits_2^3 {\sqrt {9{x^2} - 36} dx}, which you can easily calculate, using the hyperbolic substitution x = 2\cosh t.
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  3. #3
    Senior Member DeMath's Avatar
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    View a graphical representation of your problem

    Last edited by DeMath; February 5th 2009 at 06:35 AM.
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