area of a hyperbola
hey... i've been trying this problem for like 30 minutes and I can't seem to get it. I keep ending up with a weird integrand with 12 (sec cubed x -sec x). Can someone explain how to go about this? (we're doing trigonomentric substitution in calc 2)
Find the area of the region bounded by the hyperbola 9x2 - 4y2 = 36 and the line x = 3.
You should have received this integral , which you can easily calculate, using the hyperbolic substitution .
Originally Posted by chubigans