I am beyond lost how to find critical points of problems such as this http://www.baruch.cuny.edu/webwork2_...3a7edba161.png
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Originally Posted by AMAZINGigorr I am beyond lost how to find critical points of problems such as this http://www.baruch.cuny.edu/webwork2_...3a7edba161.png Use the first derivation: $\displaystyle h(x)=\sqrt{2-7x^2}~\implies~h'(x)=\frac12 \cdot (2-7x^2)^{-\frac12} \cdot (-14x) = \dfrac{-7x}{\sqrt{2-7x^2}}$ h'(x) = 0 if x = 0 Now check if you've got a minimum or a maximum. I'll leave this part for you.
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