y=ln[(e^x +1)/(e^x -1)]
interval [ln2,ln3]
please help
thanks
I'll assume your work is fine.
Now, to integrate that, just observe that $\displaystyle \frac{{{e}^{2x}}+1}{{{e}^{2x}}-1}=\frac{{{e}^{x}}+{{e}^{-x}}}{{{e}^{x}}-{{e}^{-x}}}$ and by differentiating $\displaystyle e^x-e^{-x}$ you'll get $\displaystyle e^x+e^{-x}$ which is the numerator, so I think you know what's the proper substitution.