y=ln[(e^x +1)/(e^x -1)]

interval [ln2,ln3]

please help

thanks

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- Feb 3rd 2009, 08:51 PMtichuacalc2. find the arc length of a function
y=ln[(e^x +1)/(e^x -1)]

interval [ln2,ln3]

please help

thanks - Feb 3rd 2009, 08:58 PMKrizalid
I assume you know the arc-lenght formula for this case.

Show your work please, or may be an attempt. - Feb 3rd 2009, 09:04 PMtichua
y'= (-2e^x)/(e^2x - 1)

(y'^2)= [4e^(2x)]/[(e^2x - 1)^2]

sqroot of [1+ (y'^2)]= (e^2x +1) / (e^2x -1)

then i got stuck. i have no idea how to take the integral of (e^2x +1) / (e^2x -1)

thanks - Feb 5th 2009, 04:01 PMKrizalid