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Thread: trig integration

  1. #1
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    trig integration

    $\displaystyle \sigma 4sinx + cosx dx$
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  2. #2
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    Quote Originally Posted by henri View Post
    $\displaystyle \sigma 4sinx + cosx dx$
    do mean integral of that? if you do:

    $\displaystyle \int 4sinx + xcosxdx$

    $\displaystyle \int 4sinx + \int xcosxdx$

    $\displaystyle -4cosx + C +$__________

    here let $\displaystyle u=x$
    $\displaystyle du=dx$
    $\displaystyle dv=cosx$
    $\displaystyle v=sinx$

    then use integration by parts.

    can you finish from here?
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