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**calc_help123** This is a calc ab problem

f(x)= x^3+ax^2+bx+c

1)the graph of f has a point of inflection at (0,-2)

2)The average(mean) value of f(x) on the closed interval [0,2] is -3

a) determine values of a b and c

b) determine the calue of x that satisfies the conclusion of the Mean Value Theorem for f on the closed interval [0,3]

The first derivative is 3x^2+2ax+b

and the second is 6x+2a

so if you substitute 0=6(0)+2a

a= 0

also (0,-2) is a point so

-2=0+0+c

so c= -2

How would i find the rest of the information?