alright so u do uv-integral(vdu)
so,
3xsin(5x)/5-integral(sin(5x)/5*3dx
3xsin(5x)/5+3cos(5x)/25
do u understand how i got that?
or need me to explain further?
Yup, got it I was thrown off from the fact that you can just use du, you dont have to isolate and replace dx. Because of that I was using du/3 not 3du.