if f(x) = e^2x and g(x) =lnx, then the derivative of y = f(g(x)) at x=e is? no idea how to do this! thanks in advance!
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Originally Posted by LexiRae if f(x) = e^2x and g(x) =lnx, then the derivative of y = f(g(x)) at x=e is? no idea how to do this! thanks in advance! One way of doing it is substituting you get $\displaystyle f(g(x)) = \exp(2*\ln(x))$ $\displaystyle = \exp(\ln(x^2))$ $\displaystyle = x^2$ Then the derivative $\displaystyle (f(g(x))' = 2x$ So at x = e $\displaystyle (f(g(x))' = 2e$ HTH
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