g(x) = x/(1-|x|) I began by assuming not so y/(1-|y|) = x/(1-|x|) but came unstuck when dealing with the modulus signs - do I need to deal with the case where x<0, y>0. If so, how do I do this? thanks
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You must have copied it incorrectly. As written it is not one-to-one.
ahh sorry - its defined from -1 to 1
In that case they cannot have different signs. Note . So the numerators must have the same sign.
of course - I missed the fact it was between -1 and 1 I am also asked to find g((-1,1)) what does this mean? is it g(-1) and g(1)? I also need inverse of g.. do I need to do this with separate cases for x>0, x<0? many thanks
Originally Posted by James0502 I am also asked to find g((-1,1)) what does this mean? is it g(-1) and g(1)? First, did you graph the function? is simply the range of the function.
yes, I did.. so the range is infinity, since the graph goes from -inf to + inf?
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