Find the area between the two curves: $\displaystyle x = y^2 - 6y$ $\displaystyle x = 5y - y^2$ I have no idea where to start...
Follow Math Help Forum on Facebook and Google+
Originally Posted by topher0805 Find the area between the two curves: $\displaystyle x = y^2 - 6y$ $\displaystyle x = 5y - y^2$ I have no idea where to start... Draw a picture. Both of them are parabola's on their sides. Complete the suqare in y to put them in standard form.
Originally Posted by danny arrigo Draw a picture. Both of them are parabola's on their sides. Complete the suqare in y to put them in standard form. I was given a picture (it's a WebAssign question). How do I complete the square in this case?
Originally Posted by topher0805 Find the area between the two curves: $\displaystyle x = y^2 - 6y$ $\displaystyle x = 5y - y^2$ I have no idea where to start... $\displaystyle x = y^2 - 6 y + \left(\frac{-6}{2} \right)^2 - \left(\frac{-6}{2} \right)^2$ $\displaystyle x = (y-3)^2 - 9$ standard form $\displaystyle x + 9 = (y-3)^2 $ The vertex is located at $\displaystyle (-9,3)$
View Tag Cloud