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Math Help - tangent

  1. #1
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    tangent

    Q&A..but i have the problem to factorize 2x^3.........
    need help..
    tq for your time
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  2. #2
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    You do not have to solve the simultaneous equation, but you need it.

    From the data, we know that y = 4x -26.
    This means the gradient (which is constant for a straight line) is 4 at any point (including point P)

    We also know that we can obtain the gradient at point P by differentiating it, then substituting the x value of the point in. Thus
    y' = 6x - 6x -12 = 4 for point P (x,y)
    Solve for x to find the horizontal value for P

    You will get two different values of x

    Now substitute that value of x into your simultaneous equation, and only one of them will satisfy the equation. That is the x value of point P.
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  3. #3
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    Tq

    Gusbob, i will try to correct it. tq for your guide
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