A rectangular sheet of metal measures 6cm by 8cm. Four equal squares are cut from each corner of the sheet (so it looks like a net of a rectangular prism, without the lid) and the remaining metal is bent to form an open ended rectangular tray. (so the equation of the volume would be V=4x(4-x)(3-x)]
I) What would be the largest possible value of x?
II) What would be the smallest possible value of x?
Is there a way to do this without calculus?
The volume is calculated by:
Originally Posted by requal
The three factors correspond to the edges of the box and must be positive (or zero).
Therefore the smallest possible length of x is x = 0, but then the volume is zero too. Actually you leave the metal sheet untouched.
The largest possible length of x is x = 3, but then the width of the box is zero and consequently the volume is zero too. Actually you fold the sheet of metal once.
Thus the domain of V is