If g(x,y) = ln (ye^xy) g sub x = ? My answers show it is simply y but I do not understand why. I thought since the derv of a ln is 1/(ye^xy) and since y is constant in this case the answer should be 1/e^x?????????

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- Feb 1st 2009, 08:10 PMFrostkingpartial derivative question
If g(x,y) = ln (ye^xy) g sub x = ? My answers show it is simply y but I do not understand why. I thought since the derv of a ln is 1/(ye^xy) and since y is constant in this case the answer should be 1/e^x?????????

- Feb 1st 2009, 08:16 PMChris L T521
- Feb 1st 2009, 11:09 PMFrostkingdifferential question answer
Yes, thank you I did not realize that you should split into two natural logs and I did not know that the ln e^xy is simply xy. Thanks much! Frostking