Results 1 to 2 of 2

Thread: Finding Differentiable Values

  1. #1
    Newbie
    Joined
    Jan 2009
    Posts
    18

    Finding Differentiable Values

    Find all values of x for which the function y=(the square root of x)/(5x-2) is differentiable.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Junior Member star_tenshi's Avatar
    Joined
    Jan 2009
    Posts
    32
    Quote Originally Posted by CalcQueen View Post
    Find all values of x for which the function y=(the square root of x)/(5x-2) is differentiable.
    In order for $\displaystyle y$ to be differentiable, then $\displaystyle y$ and $\displaystyle y'$ must be defined, or real.
    For $\displaystyle y$, the numerator confines anything inside the squareroot to be greater than or equal to zero: $\displaystyle x \geq 0$.
    When the denominator equals to zero, we know the function becomes undefined. This occurs when $\displaystyle 5x-2 = 0 \Rightarrow x = \frac{2}{5}$
    Thus our conditions are: $\displaystyle x \geq 0$, $\displaystyle x$ not equal to $\displaystyle \frac{2}{5}$

    Upon differentiating to $\displaystyle y'$, we can see that the same conditions for $\displaystyle x$ are required for $\displaystyle y'$ to be defined.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 3
    Last Post: Jul 6th 2011, 06:48 PM
  2. Replies: 9
    Last Post: Dec 17th 2010, 08:13 AM
  3. Replies: 4
    Last Post: Jun 19th 2010, 05:25 AM
  4. Differentiable Eq. finding function f
    Posted in the Calculus Forum
    Replies: 1
    Last Post: Dec 1st 2008, 09:22 PM
  5. Replies: 3
    Last Post: Sep 26th 2008, 11:00 PM

Search Tags


/mathhelpforum @mathhelpforum