1/(x*sqrt(x)) I am thinking it is equal to x^(-3/2) so the integral should be -1/2x^(-1/2) + C but thats apparently not correct
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Originally Posted by TYTY 1/(x*sqrt(x)) I am thinking it is equal to x^(-3/2) so the integral should be -1/2x^(-1/2) + C but thats apparently not correct Be careful... $\displaystyle \int x^{-\frac{3}{2}}\,dx=\frac{x^{\frac{-1}{2}}}{-\frac{1}{2}}+C=\dots$
Originally Posted by TYTY 1/(x*sqrt(x)) I am thinking it is equal to x^(-3/2) so the integral should be -1/2x^(-1/2) + C but thats apparently not correct $\displaystyle \int x^{- \frac{3}{2}}\, dx = \frac{x^{- \frac{1}{2}}}{- \frac{1}{2}} + c = -2 x^{- \frac{1}{2}} + c$ Better.
Last edited by Jester; Feb 1st 2009 at 11:01 AM. Reason: Too slow
Originally Posted by Chris L T521 Be careful... $\displaystyle \int x^{-\frac{3}{2}}\,dx=\frac{x^{\frac{-1}{2}}}{-\frac{1}{2}}+C=\dots$ crap, I multiplied instead of dividing what an idiot (me) thank you
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